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exercises/dp/backpack_dp/NOIP2005J_herbs_dp_knapsack_MWASTE_BETTER.cpp
T
2026-09-05 11:05:50 +08:00

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C++

/*
* 背包 DP:考虑前 i 个物品的最大价值,在仅有 t 容量的情况下。
*/
#include <iostream>
using namespace std;
struct Item {
int weight, value;
};
constexpr int MAX_N = 105, MAX_CAPACITY = 1005;
int capacity, n;
Item items[MAX_N];
int dp[MAX_N][MAX_CAPACITY];
void log_dp() {
for (int i = 0; i <= n; i++) {
for (int j = 0; j <= capacity; j++) {
clog << dp[i][j] << "\t";
}
clog << endl;
}
}
void solve_dp() {
for (int i = 0; i <= capacity; i++) { dp[0][i] = 0; }
for (int i = 0; i <= n; i++) { dp[i][0] = 0; }
for (int stop_item = 1; stop_item <= n; stop_item++) {
for (int w = 1; w <= capacity; w++) {
dp[stop_item][w] = dp[stop_item - 1][w];
if (w >= items[stop_item - 1].weight) { // 负数
dp[stop_item][w] =
max(dp[stop_item][w],
dp[stop_item - 1][w - items[stop_item - 1].weight] + items[stop_item - 1].value);
}
}
}
}
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
cin >> capacity >> n;
for (int i = 0; i < n; i++) {
cin >> items[i].weight >> items[i].value;
}
solve_dp();
log_dp();
cout << dp[n][capacity] << endl;
return 0;
}