some programs!!!

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rogerwang2008 committed 2026-10-09 10:21:51 +08:00
1 parent 71f1022dea
commit ca6daa582c
43 files changed
+1452 -381

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#include <stdio.h>
#define _NOT_USED \
'''
int main() {
int a, b;
scanf("%d%d", &a, &b);
printf("%d", a + b);
return 0;
}
#define _NOT_USED \
'''
#define _NOT_USED /*
a, b = map(int, input().split())
print(a + b)
#*/
-50
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#include <stdio.h>
int main() {
long long T; //注意变量都要初始化 ,T为数组个数
scanf("%lld", &T); //数组个数,决定过程要执行多少次
for (int i = 0; i < T; i++) {
long long n, m, bianhao, yushu, max = -1, index; //注意变量都要初始化,n为包裹个数,m为箱子个数,result是余数,max是装的最多
//以上变量必须定义在循环里,因为一组过后所有数据要重新开始!要不然max,index值未清除!
scanf("%lld%lld", &n, &m); //键入包裹的个数和箱子的个数
long long Amount[m], number[n]; //Amount是定义对应的箱子里装几个 ,number是用数组记录包裹的“编号”
//禁止写错数组个数!
for (int j = 0; j < m; j++) //初始化箱子数组 ,注意数组是m个
{
Amount[j] = 0;
}
for (int k = 0; k < n; k++) //把包裹赋值,记录到number里 注意数组是n个
{
scanf("%lld", &bianhao);
number[k] = bianhao;
}
for (int s = 0; s < n; s++) //进行mol m运算,余数计入number里
{
yushu = number[s] % m;
Amount[yushu] = Amount[yushu] + 1;
}
for (int t = 0; t < m; t++) //此循环计算哪个箱子装的最多
{
//max=-1;错误 在循环里定义会导致max每走一个t都会被重置!
if (max < Amount[t]) {
max = Amount[t];
}
}
for (int u = 0; u < m; u++) //此循环寻找下标
{
if (Amount[u] == max) {
index = u;
break;
}
}
for (int v = 0; v < m; v++) //此循环输出amount数组里各个元素的大小
{
printf("%lld ", Amount[v]);
}
printf("\n");
printf("%lld %lld", index, max);
printf("\n");
}
return 0;
}
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#include <bits/stdc++.h>
using namespace std;
constexpr float ALLOWED_DIFF = 1e-6;
std::tuple<int, double> sqrt_custom(double x) {
double est_prev = -1, est_curr = x;
int rounds = 0;
while (abs(est_curr - est_prev) > ALLOWED_DIFF) {
est_prev = est_curr;
// est_curr = 0.5 * (est_prev + x / est_prev);
est_curr = x / (2 * est_curr) + 0.5 * est_curr;
rounds++;
}
return std::make_tuple(rounds, est_curr);
}
int main() {
std::ios::sync_with_stdio(false);
std::cin.tie(nullptr);
int x;
while (std::cin >> x) {
auto [rounds, ans] = sqrt_custom(x);
std::cout << rounds << " " << std::fixed << std::setprecision(2) << ans << std::endl;
}
return 0;
}