some programs!!

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rogerwang2008 committed 2026-09-28 14:05:06 +08:00
1 parent ed054247d5
commit 71f1022dea
38 files changed
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#include <stdio.h>
int main() {
long long T; //注意变量都要初始化 ,T为数组个数
scanf("%lld", &T); //数组个数,决定过程要执行多少次
for (int i = 0; i < T; i++) {
long long n, m, bianhao, yushu, max = -1, index; //注意变量都要初始化,n为包裹个数,m为箱子个数,result是余数,max是装的最多
//以上变量必须定义在循环里,因为一组过后所有数据要重新开始!要不然max,index值未清除!
scanf("%lld%lld", &n, &m); //键入包裹的个数和箱子的个数
long long Amount[m], number[n]; //Amount是定义对应的箱子里装几个 ,number是用数组记录包裹的“编号”
//禁止写错数组个数!
for (int j = 0; j < m; j++) //初始化箱子数组 ,注意数组是m个
{
Amount[j] = 0;
}
for (int k = 0; k < n; k++) //把包裹赋值,记录到number里 注意数组是n个
{
scanf("%lld", &bianhao);
number[k] = bianhao;
}
for (int s = 0; s < n; s++) //进行mol m运算,余数计入number里
{
yushu = number[s] % m;
Amount[yushu] = Amount[yushu] + 1;
}
for (int t = 0; t < m; t++) //此循环计算哪个箱子装的最多
{
//max=-1;错误 在循环里定义会导致max每走一个t都会被重置!
if (max < Amount[t]) {
max = Amount[t];
}
}
for (int u = 0; u < m; u++) //此循环寻找下标
{
if (Amount[u] == max) {
index = u;
break;
}
}
for (int v = 0; v < m; v++) //此循环输出amount数组里各个元素的大小
{
printf("%lld ", Amount[v]);
}
printf("\n");
printf("%lld %lld", index, max);
printf("\n");
}
return 0;
}
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#include <iostream>
using namespace std;
int primes[2001];
bool is_prime(int a) {
for (int i = 2; i * i <= a; i++) {
if (a % i != 0) {
continue;
} else {
return false;
}
}
return true;
}
void init_primes() {
int current_num = 2, i = 0;
for (;; current_num++) {
if (is_prime(current_num)) {
primes[i] = current_num;
i++;
}
}
}
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int a;
cin >> a;
if (a % 2 != 0 || a < 6) {
cout << "Error!" << endl;
} else
for (int i = 0; primes[i] <= a / 2; i++) {
if (is_prime(a - primes[i])) {
cout << a << "=" << i << "+" << a - i << endl;
}
}
return 0;
}
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#include <iostream>
using namespace std;
// x[0]..x[99]
bool is_prime(int n) {
for (int i=2; i*i<=n; i++) {
if (n%i == 0) {return false;}
}
return true;
}
int main() {
cout << is_prime(4);
return 0;
}